URI online judge solution1011 Sphere solution
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URI online judge solution1011 Sphere solution
Beecrowd 1011 Sphere Solution in C: A Comprehensive Guide
At its core, programming is about solving problems. In this article, we’ll take a deep dive into the solution for the Beecrowd 1011 Sphere problem in C. We’ll start with a brief overview of the problem, then walk through the solution step-by-step, and finally offer some tips for improving the efficiency of the code.
Overview of the URI/Beecrowd online judge solution1011 Sphere solution in C
The Beecrowd 1011 Sphere problem is a classic problem in programming. It involves calculating the volume of a sphere with a given radius. Here’s the problem statement:
You have to calculate and print the volume of a sphere given its radius R. The formula to calculate the volume is (4/3) * pi * R^3. Consider (assign) for this problem that π = 3.14159.
Now let’s dive into the solution.
URI online judge solution1011 Sphere solution in C
#include<stdio.h>
int main() {
double R,pi,v;
pi=3.14159;
scanf("%lf",&R);
v=(4.0piRRR)/3;
printf("VOLUME = %.3lf\n",v);
return 0;
}
URI online judge solution1011 Sphere solution in C
Tips for Improving the Efficiency of the Code
While the above solution works perfectly fine for the URI online judge solution1011 Sphere solution in C, there are a few ways we can optimize the code for efficiency. Here are some tips:
- Use the pow() function to calculate the cube of the radius instead of multiplying it by itself three times. This can improve the readability of the code and make it easier to modify in the future.
- Use a constant instead of initializing pi every time the program runs. This can improve the efficiency of the program by reducing the amount of memory and CPU time required.
- Use meaningful variable names to make the code easier to read and understand. For example, we could use “radius” instead of “R” to make the purpose of the variable more clear.
- Use comments to explain the purpose and functionality of the code. This can make it easier for others to understand and modify the code in the future.
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