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  Beecrowd 1012-Area solution C, CPP and Python Question link beecrowd | 1012 Area Make a program that reads three floating point values: A, B and C. Then, calculate and show: a) the area of the rectangled triangle that has base A and height C. b) the area of the radius’s circle C. (pi = 3.14159) c) the area of the trapezium which has A and B by base, and C by height. d) the area of ​​the square that has side B. e) the area of the rectangle that has sides A and B. Input The input file contains three double values with one digit after the decimal point. Output The output file must contain 5 lines of data. Each line corresponds to one of the areas described above, always with a corresponding message (in Portuguese) and one space between the two points and the value. The value calculated must be presented with 3 digits after the decimal point. Input Samples Output Samples 3.0 4.0 5.2 TRIANGULO: 7.800 CIRCULO: 84.949 TRAPEZIO: 18.200 QUADRADO: 16.000 RETANGULO: 12.000 12.7 10.4 15.2 TRIANG

  online judge solutions Codeforces https://freecodecenter.com/online-judge-solutions/codeforces-problem-solution/ Codeforces is a popular online platform for competitive programming, which hosts regular coding competitions and challenges for programmers of all levels. It was founded in 2009 by a group of Russian programmers and has since grown into a global community of over 1.5 million registered users. The platform offers a variety of coding challenges, ranging from algorithmic problems to more specialized topics such as machine learning and artificial intelligence. Users can compete in individual or team contests, participate in virtual competitions, and even create their own contests. BEECROWD Problems Solution/URI Solution https://freecodecenter.com/online-judge-solutions/beecrowd-problems/

  BEECROWD 1002 – Area of a Circle solution BEECROWD 1002 – Area of a Circle solution 100% Accepted BEECROWD 1002 – Area of a Circle Question Introduction In this article, we will present a comprehensive solution for  URI Online Judge problem 1002  in C, C++, Java, C#, and Python. This problem requires us to calculate the area of a circle given its radius. Our solution is optimized for efficiency and accuracy, and it can be easily adapted to different programming languages and platforms. Solution Overview Our solution consists of a single function that takes the radius as input and returns the area of the circle. The function uses the mathematical formula A = π . R² to calculate the area, where π is a constant value of 3.14159. The function is implemented in a way that maximizes performance and minimizes errors, making it suitable for large-scale calculations and real-time applications. Solution Implementation Here is the implementation of our solution in C, C++, Java, C#, and Python:

  Beecrowd1009 – Salary with Bonus solution with C problem question #include<stdio.h> int main() { double a,b,c; char name; scanf("%s %lf %lf",&name,&a,&b); c=b*.15+a; printf("TOTAL = R$ %.2lf\n",c); return 0; } Beecrowd 1026 To Carry or not to Carry Solution Programming Quotes BEECROWD 1002 – Area of a Circle solution

  URI online judge solution1011 Sphere solution Beecrowd 1011 Sphere Solution in C: A Comprehensive Guide At its core, programming is about solving problems. In this article, we’ll take a deep dive into the solution for the  Beecrowd 1011 Sphere  problem in C. We’ll start with a brief overview of the problem, then walk through the solution step-by-step, and finally offer some tips for improving the efficiency of the code. Overview of the URI/Beecrowd online judge solution1011 Sphere solution in C The Beecrowd 1011 Sphere problem is a classic problem in programming. It involves calculating the volume of a sphere with a given radius. Here’s the problem statement: You have to calculate and print the volume of a sphere given its radius R. The formula to calculate the volume is (4/3) * pi * R^3. Consider (assign) for this problem that π = 3.14159. Now let’s dive into the solution. URI online judge solution1011 Sphere solution in C #include<stdio.h> int main() { double R,pi,v; pi=3.